(12x^2+40x+25)/(2x+5)

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Solution for (12x^2+40x+25)/(2x+5) equation: 


D( x )

2*x+5 = 0

2*x+5 = 0

2*x+5 = 0

2*x+5 = 0 // - 5

2*x = -5 // : 2

x = -5/2

x in (-oo:-5/2) U (-5/2:+oo)

(12*x^2+40*x+25)/(2*x+5) = 0

12*x^2+40*x+25 = 0

12*x^2+40*x+25 = 0

DELTA = 40^2-(4*12*25)

DELTA = 400

DELTA > 0

x = (400^(1/2)-40)/(2*12) or x = (-400^(1/2)-40)/(2*12)

x = -5/6 or x = -5/2

(x+5/2)*(x+5/6) = 0

((x+5/2)*(x+5/6))/(2*x+5) = 0

( x+5/2 )

x+5/2 = 0 // - 5/2

x = -5/2

( x+5/6 )

x+5/6 = 0 // - 5/6

x = -5/6

x in { -5/2} 

x = -5/6

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